WebEngineering and Computer Science Program Website (www.EngrCS.com) Web3.26. For the circuit shown in Fig. P3.26, both diodes are identical, conducting 10mA at 0.7V, and 100mA at 0.8V. Find the value of R for which V = 80mV. V1 is the voltage …
Chapter 4, Problem 45 - AppServ Open Project 2.6.0 - Studylib
WebAssuming the voltages are defined relative to the original S and D terminals as in Fig. P4.11(b), VGS = 2 - (-0.5) = 2.5 V, VGS - VTN = 2.5 - 1 = 1.5 V, and VDS = 0.5 V --> triode region (f) The source and drain of the transistor are again reversed because of the sign change in VDS. Webwww.elsolucionario.net www.elsolucionario.net ale29559_IFC.qxd 07/11/2008 07:40 PM Page 2 PRACTICAL APPLICATIONS • • • • • • • • • • • • • • • • • • • • • • • • • • • • • Rechargeable flashlight battery (Problem 1.11) Cost of operating toaster (Problem 1.25) Potentiometer (Section 2.8) Design a lighting system (Problem 2.61) Reading a ... graphite drawings of birds
prob4-28s - Problem 4.28 For the circuit in Fig. P4.28,...
WebStep-by-step solution. 100% (34 ratings) for this solution. Step 1 of 5. Refer to Figure 4.96 in the textbook. Use source transformation to convert dependent current source, in parallel with to dependent voltage source in series resistor. Calculate the value of voltage source. WebProblem 4.28 For the circuit in Fig. P4.28, generate a plot for υ L as a function of υ s over the full linear range of υ s. v s v o R L v L 20 k Ω 4 k Ω 4 V 0.5 V V cc = 12 V + _ + _ + _ Figure P4.28: Circuit for Problem 4.28. Web3.26. For the circuit shown in Fig. P3.26, both diodes are identical, conducting 10mA at 0.7V, and 100mA at 0.8V. Find the value of R for which V = 80mV. V1 is the voltage across diode 1, V2 across diode 2, I1 is current through diode 1, and I2 through diode 2. Then we have (using exponential model) I = I1 +I2 I2 = Is exp V2 nVT I1 = Is exp V2 ... graphite drawing definition